Question 714769
Elliott street is 24ft wide when it ends at main street in brattleboro, vermont, a 40 ft long diagonal crosswalk allows pedestrians to cross main street to or from either corner of elliott street. determine the width of main street 
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Let m = the width of Main street
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draw this out marking the width of Elliot as 24 and the width of Main as m
The diagonal, the distance to opposite corners, is 40
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Find the angle (A) enclosed by the diagonal (40) and the width of Elliot (24)
Use the cosine for this
Cos(A) = {{{24/40}}}
A = 53.13 degrees
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Find the width of Main street using the sine of this angle
Sin(53.13) = {{{m/40}}}
.8 = {{{m/40}}}
m = .8 * 40
m = 32 ft is the width of main street