Question 714697
-------------- 	percent	----------------	Amount									
Amtifreeze I	20	----------------			70	gal						
Antifreeze II	70	----------------			x	gal						
Mixture	60	----------------	70	+	x	gal						
												
20	*	70	+	70	x	=	60	(	70	+	x	)
1400	+	70	x	=	4200	+	60	x				
70	x		-60	x	=	-1400	+	4200				
10	x	=	2800									
/	10											
x	=	280		gal	Antifreeze II							
												
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