Question 714624
{{{y=8x^2+16x}}} To find the roots solve y=0

{{{8x(x+2)=0}}} the roots are x=0 or x=-2

The vertex is the point (x,y) where {{{x=-b/2a}}} 

{{{x=-16/16}}} 

{{{x=-1}}},and 

{{{y=8(-1)^2+16(-1)}}} 

{{{y=-8}}}.