Question 714176
find the slant asymptote of the graph of the rational function and Use the slant asymptote to graph the rational function. 
f(x)= (x^2-x-20)/(x-6)
f(x)=(x-5)(x+4)/(x-6)
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b.) first determine the symmetry of the graph of f.
Graph has no symmetry as can be seen by the graph below.
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c.) find the x and y-intercepts
y-intercept:
set x=0
y-intercept=-20/-6=10/3
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x-intercept:
set y=0
x^2-x-20
(x-5)(x+4)=0
x-intercepts at 5 and-4
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d.) find the asymptotes.
vertical asymptote:
set denominator=0, then solve for x
x-6=0
vertical asymptote: x=6
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slant asymptote:
divide numerator by denominator:
(x^2-x-20)/(x-6)=(x+5)+remainder
slant asymptote: y=x+5
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number line
<...-....-4....+.....5....-.....6....+.....>



{{{ graph( 300, 300, -50, 50, -50, 50, (x^2-x-20)/(x-6)) }}}