Question 714331
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For each of your inequalities, select a point that is NOT on the boundary line -- i.e. the line formed by graphing the inequality as if it were an equation.  Substitute the coordinates of the ordered pair representing the selected point into the inequality and then do any indicated arithmetic.  If the result is a TRUE statement, then shade in the side of the boundary line that CONTAINS the selected point.  Otherwise, shade in the OTHER side.  The area of feasibility for the set of inequalities is that area where ALL of the shaded areas overlap.  If finding this overlap area is the goal of the exercise, then many times it is easier to see the overlap area if you shade in all of the inequalities OPPOSITE to the given sense.  That way, the feasible area, if there is one, is the only UNSHADED region on the plane.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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