Question 714246
<pre>
|x| + |y| = 2

We find the x-intercepts by setting y=0

|x| + |0| = 2
      |x| = 2
        x = ±2

So the x-intercepts are (2,0) and (-2,0)

We find the y-intercepts by setting x=0

|0| + |y| = 2
      |y| = 2
        y = ±2

So the y-intercepts are (0,2) and (0,-2) 

We plot those:

{{{drawing(400,400,-3,3,-3,3, graph(400,400,-3,3,-3,3),
circle(2,0,.05),circle(-2,0,.05),circle(0,2,.05),circle(0,-2,.05) )}}}

We find some more points.

Let x=1 and solve for y

|1| + |y| = 2
  1 + |y| = 2
      |y| = 1
        y = ±1  so we have the points (1,1) and (1,-1)

Let x=-1 and solve for y

|-1| + |y| = 2
   1 + |y| = 2
       |y| = 1
         y = ±1  so we have the points (-1,1) and (-1,-1)

We plot those four points:

{{{drawing(400,400,-3,3,-3,3, graph(400,400,-3,3,-3,3),
circle(2,0,.05),circle(-2,0,.05),circle(0,2,.05),circle(0,-2,.05),
circle(1,1,.05),circle(-1,1,.05),circle(1,-1,.05),circle(-1,-1,.05)

 )}}}

And we sketch in the graph:

{{{drawing(400,400,-3,3,-3,3, graph(400,400,-3,3,-3,3),
circle(2,0,.05),circle(-2,0,.05),circle(0,2,.05),circle(0,-2,.05),
circle(1,1,.05),circle(-1,1,.05),circle(1,-1,.05),circle(-1,-1,.05),
line(0,2,2,0),line(-2,0,0,-2), line(2,0,0,-2),line(-2,0,0,2) )}}}

Edwin</pre>