Question 714235
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\Delta y}{\Delta x}\ =\ \frac{f(x\ +\ t)\ -\ f(x)}{t}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\Delta y}{\Delta x}\ =\ \frac{(x^2\ +\ 2tx\ +\ t^2\ +\ x\ +\ t)\ -\ (x^2\ +\ x)}{t}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\Delta y}{\Delta x}\ =\ \frac{2tx\ +\ t^2\ +\ t}{t}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\Delta y}{\Delta x}\ =\ 2x\ +\ t\ +\ 1]


From *[tex \LARGE x\ =\ 3] to *[tex \LARGE x\ +
 t\ =\ 7], so *[tex \LARGE 3\ +\ t\ = 7], hence *[tex \LARGE t\ =\ 4]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\Delta y}{\Delta x}\ =\ 2(3)\ +\ (4)\ +\ 1\ =\ 11]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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