Question 714130
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Let *[tex \LARGE x] represent the number of cakes and let *[tex \LARGE y] represent the number of pies.  Then *[tex \LARGE 3x] dollars is the production cost for cakes and *[tex \LARGE 4y] dollars is the production cost for pies.  Since total production costs must not exceed $120, we can say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 4y\ \leq\ 120]


Furthermore, you cannot make a negative number of either cakes or pies, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ \geq\ 0]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ \geq\ 0]


Graph the three inequalities.  The area where the three solution sets overlap is the area of feasibility for the problem.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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