Question 63056
Factor:
{{{9p^6 - 72p^3}}} Factor out {{{9p^3}}}
{{{9p^3(p^3-8)}}} Notice that the {{{(p^3-8)}}} is the difference of two cubes: {{{(p)^3 - 2^3}}} which can be factored.
{{{9p^3(p-2)(p^2+2p+4)}}}...and we're done!