Question 714044
If you draw a rectangle, (go on, draw one!) and label the lengths as l and the widths as w, then the perimeter is 
l+w+l+w or, simplifying this we get 2l+2w removing the common factor gives
2(l+w) this = 66m
dividing both sides by 2 gives
l + w = 33
rearranging this gives us
l = 33 - w  let's call this equation (1)
Now.....
the area of a rectangle is l*w, this is = 270
i.e.
l * w = 270 let's call this equation (2)
using equation (1) in equation (2) gives
(33-w) * w = 270
multiplying out the bracket gives
{{{33w - w^2 = 270}}}
rearranging this equation gives
{{{w^2 - 33w + 270 = 0}}} 
using the formula for quadratics
{{{w = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
gives
w = 18 or 15
since the width must be smaller than the length
this gives the length as 18 m and the width = 15 m