Question 713399
Assume that the mean and the standard deviation of a dataset are 45 and 6, respectively. Without assuming anything about the distribution of the data, at least what percentage of the values is between 33 and 57? 
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(57-45)/6 = 12/6 = 2
(45-33)/6 = 12/6 = 2
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Those values frame 2 standard deviations of data around the mean.
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According to Chebychev at least 75% of the data is between
those 2 values.
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Cheers,
Stan H.
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