Question 713104
{{{(2x+29)/3}}} = {{{(x+44)/8}}} + 2. solve for x.
multiply by 24 to get rid of the denominators
24*{{{(2x+29)/3}}} = 24*{{{(x+44)/8}}} + 24(2)
cancel the denominators
8(2x+29) = 3(x+44) + 48
16x + 232 = 3x + 132 + 48
16x - 3x = 132 + 48 - 232
13x = -52
x = -52/13
x = -4
:
;
Check this in the original equation, replace x with -2
{{{(2(-4)+29)/3}}} = {{{(-4+44)/8}}} + 2.
I'll let you do the math here to confirm our solution of x = -4