Question 713064
 cylindrical standpipe is contain 343000 gal. of water. If its height is to be twice it diameter, what must be its dimension?
:
the vol of a cylinder: {{{V = pi*r^2*h}}}
h = twice the diameter which is 4 times the radius
therefore
{{{pi*r^2*4r}}} = 342000
divide both sides by 4pi, resulting in
{{{r^3}}} = 27295
find the cube root
r = 30.11
:
Diameter = 60.22
height: = 120.44
:
Check
{{{pi*30.11^2*120.44}}} = 343038 ~ 343000