Question 712917
if cot = - 3/4 and 90 degress < theta < 180 degrees, find sin theta
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We are working with a reference angle in quadrant II where cot<0 and sin>0
let O=opposite side
let A=adjacent side
let H=hypotenuse
..
cot theta=-3/4=A/O
A=-3, O=4
H=&#8730;(A^2+O^2)=&#8730;(9+16)=&#8730;25=5
You are working with a 3-4-5 right triangle in quadrant II
sin theta=O/H=4/5