Question 712831
Use the known formulas and then substitute your value.


A for area, r for radius
{{{A=pi*r^2}}} and {{{2r=diameter}}}.


{{{r^2=A/(pi)}}}
{{{r=sqrt(A/pi)}}}
diameter is {{{highlight(2*sqrt(A/pi))}}}, which is the same as the inside length needed of the pizza box.