Question 712648
Let the width of sidewalk be x															
..															
Length of pool =			10	m  											
Width =			12	m  											
															
Area =			120		m^2										
Area of sidewalk =			104	m^2											
Length of pool + sidewalk =							10	+	2	x 					
width of pool + sidewalk =				12	+	2	x								
															
(	10	+	2	x	)	(	12	+	2	x	)	+	-120	=	104
															
	120	+	20	x	+	24	x	+	4	X^2		+	-120	=	104
	4	X^2		+	44	x	+	-104	=	0					
	Find the roots of the equation by quadratic formula														
	a=	4	b=	44	c=	-104									
	b^2-4ac=	1936	-	-1664											
	b^2-4ac=	3600			{{{sqrt(	3600	)}}}=	60							
	{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}														
	{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}														
	x1=(	-44	+	60	)/	8									
	x1=	2.00													
	x2=(	-44	-60	) /	8										
	x2=	-15.5													
	Ignore negative value														
	width of sidewalk =		2	m