Question 712539
point (7,2) and perpendicular to y = 5x - 6


Perpendicular lines have slopes which are negative reciprocals


y = 5x - 6
slope = 5
perpendicular slope is -1/5


(7,2), m = -1/5
y - y1 = m(x - x1) {point-slope form}
y - 2 = (-1/5)(x - 7) {substituted point and slope into point-slope form}
y - 2 = (-1/5)x + 7/5 {used distributive property}
y = (-1/5)x + 17/5 {added 2, which is 10/5, to each side}
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