Question 712502
 inverse operation of:
{{{f(x)=(1/5)x+12}}}
y = f(x)
{{{y=(1/5)x+12}}}
Exchange x and y and solve for y
{{{x=(1/5)y+12}}}
multiply both sides by 5
5x = y + 60
5x - 60 = y or
y = 5x - 60; is the inverse
:
looks like this
{{{ graph( 300, 300, -100, 100, -100, 100, .2x+12, 5x-60) }}}