Question 712126
 the slope and y intercept slope of -6 and goes through the point (5, 12)
Use the point/slope form: y - y1 = m(x - x1), where
m = -6; x1 = 5; y1 = 12
so we have:
y - 12 = -6(x - 5)
y - 12 = -6x + 30
y = -6x + 30 + 12
y = -6x + 42, the equation in the slope/intercept form
:
(7, 3) and (5, 4)
Find the slope using the formula: m = {{{(y2-y1)/(x2-x1)}}}, where
x1 = 7; y1 = 3
x2 = 3; y2 = 4
so we have;
m = {{{(4-3)/(5-7)}}} = {{{1/(-2)}}} OR {{{-1/2}}} is the slope (m)
Use the point/slope form: y - y1 = m(x - x1), where
m = -1/2; x1 = 7; y1 = 3
so we have
y - 3 = {{{-1/2}}}(x - 7) 
y - 3 = {{{-1/2}}}x + {{{7/2}}}
y  = {{{-1/2}}}x + {{{7/2}}} + 3
which is
y  = {{{-1/2}}}x + {{{7/2}}} + {{{6/2}}}
y  = {{{-1/2}}}x + {{{13/2}}}
or
y = -.5x + 6.5; the equation in slope/intercept form
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