Question 712308
Hello, 
Let's set this f(x)= x^3+4x^2-5x  up as:
0= x^3+4x^2-5x 
Now factor:
0= x(x^2+4x-5)
Now factor again:
0= x(x+5)(x-1)
Solve for x
x=-5
x=1
Make sense?
RJ
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