Question 712237
{{{(a^2b^3)^5*(a^-5)^2}}}


={{{a^(2*5)b^(3*5)*(1/a^5)^2}}}


={{{a^10b^15*(1^1/a^10)}}}


={{{cross(a^10)b^15*(1/cross(a^10))}}}


={{{b^15}}}