Question 62946
Using the quadratic regression capability of a TI-83 I get
y=6.691x^2+341.518x+1.000
Cheers,
Stan H.
Comment: Another way to do this problem would be to 
select 3 points, substitute their x-y values into 
y=ax^2+bx+c, thus generating three equations with 
three (a,b,c) unknows: then solving the system for 
a, b, and c.