Question 712176
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} this is the quadratic formula
{{{ax^2+bx+c=0}}} find a,b, and c in {{{3x^2-x-2=0}}}
a=3
b=-1
c=-2
Plug values into the equation and solve
{{{x = (-(-1) +- sqrt( -1^2-4(3)(-2) ))/(2*3) }}} Simplify
{{{x = (1 +- sqrt(25))/(6) }}}
{{{x = (1 +- 5)/(6) }}}
{{{1/6 +5/6 = 6/6 = 1}}}
{{{x=1}}}
{{{1/6-5/6 = -4/6 = -2/3}}}
{{{x=-2/3}}}
{-2/3,1}