Question 711964
If it is a parabola, give it's vertex, focus, and directrix; if it is an ellipse, give it's center, vertices, and foci; if it's a hyperbola, give it's center, vertices, foci, and asymptotes 
The problem: 
x^2 + 4y = 4
x^2 = -4y+4
x^2=-4(y-1)
This is an equation of a parabola that opens down.
Its standard form: (x-h)^2=-4p(y-k), (h,k)=(x,y) coordinates of the vertex
vertex: (0,1)
axis of symmetry:x=0 or y-axis
4p=4
p=1
focus: (0,0)(p-distance below vertex on the axis of symmetry)
directrix: y=2 (p-distance above vertex on the axis of symmetry)