Question 712007
I need to write an equation for a hyperbola that has the vertices (-4,1) and (-4,9) and foci at (-4,5±√97)
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Given hyperbola has a vertical transverse axis.
Its standard form:{{{(y-k)^2/a^2-(x-h)^2/b^2=1}}}, (h,k)=(x,y) coordinates of center.
..
x-coordinate of center=-4
y-coordinate of center=5 (midpoint between 1 and 9)
center: (-4,5)
length of transverse axis=8 (from 1 to 9)=2a
a=4
a^2=16
..
c=√97 (distance from center to foci)
c^2=97
c^2=a^2+b^2
b^2=c^2-a^2=97-16=81
Equation of given hyperbola:
{{{(y-5)^2/16-(x+4)^2/81=1}}}