Question 711844
Let {{{ W }}} = the width
Let {{{ L }}} = the length
{{{ 2W + 2L = 18 }}}
{{{ W + L = 9 }}}
{{{ L = 9 - W }}}
The area is expressed as
{{{ A = W*L }}}
{{{ A = W*( 9 - W ) }}}
If I can only use whole numbers, then I am limited to:
{{{ W = 1 }}}, {{{ L = 8 }}}
{{{ W = 2 }}}, {{{ L = 7 }}}
{{{ W = 3 }}}, {{{ L = 6 }}}
{{{ W = 4 }}}, {{{ L = 5 }}}
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That's as far as I can go, because if I say {{{ W = 5 }}},
then {{{ 9 - W = 4 }}}, and I already have that combination
Notice that the perimeter, {{{ 2W + 2L = 18 }}}
in all 4 cases, but area {{{ A = W*L }}}  is different in each case.