Question 711788
The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 3.6 L, how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level?
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let x=amt of coolant to be drained and replaced with water.
3.6-x=amt of original solution remaining in radiator.
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60%(3.6-x)+0%x=50%*3.6
2.16-.6x=1.8
.6x=.36
x=0.6
amt of coolant to be drained and replaced with water=.6 L