Question 711770
A cylindrical standpipe is to contain 343,000 gal. of water. If its height is to be twice its diameter, what must be its dimensions?
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343000 gallons =~ 45852.43 cubic ft
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{{{Vol = pi*r^2*h}}}
h = 2d = 4r
{{{Vol = 4pi*r^3 = 45852.43}}}
{{{r^3 = 11463.1/pi}}} ft
r =~ 15.395 feet 
d = 30.79 ft (inside diameter)
h = 61.58 ft