Question 711694
For this problem you could use the Pythagorean theorem.
The Pythagorean theorem states that for any right triangle {{{A^2 + B^2 = C^2}}}
Where A and B are the sides of the triangle and C is the hypotenuse.
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Use the theorem to solve for C
A = 8
B = 8
{{{A^2 + B^2 = C^2}}}
{{{8^2 + 8^2 = C^2}}}
{{{64 + 64 = C^2}}}
{{{128 = C^2}}}
Take the squar root of both sides
{{{sqrt(128) = C}}}
{{{highlight (11.31 = C)}}}
*Note that value is rounded.
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Now add all of the sides together to find the perimeter.
{{{8 + 8 + 11.31 = 27.31}}}
The perimeter is 21.31cm