Question 62934
QUESTION


Write the first four terms in the binomial expansion of (m-n)^11, expressing the result in simplified form

ANSWER: 


(m-n)^11 

=   m^11 - (11*10)/(1*2) m^10 * n^10 + (11*10*9)/(1*2*3)m^9 * n^2+(11*10*9*8)/

     (1*2*3*4 ) * m^8 *n^3+...



= m^11 -55m^10 * n^10 + 165 m^9 * n^2+ 330 * m^8 *n^3+............



 = m^11 -55m^10 n^10 + 165 m^9  n^2 - 330 m^8 n^3



which is the required answer.



Regards.

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