Question 711589
Please write the following equation in standard form.
x^2+8y^2+113=14x+48y
rearrange terms:
x^2-14x+8y^2-48y=-113
complete the square:
(x^2-14x+49)+8(y^2-6y+9)=-113+49+72
(x-7)^2+8(y-3)^2=8
{{{(x-7)^2/8+(y-3)^2=1}}}
This is an equation of an ellipse with horizontal major axis with center at (7,3)
Its standard form: {{{(x-h)^2/a^2+(y-k)^2/b^2=1}}}, a>b, (h,k)=(x,y) coordinates of center