Question 711459
<pre>
{{{((3x^2)/(5xy^5))^3}}}

Make sure every number and every letter inside the parentheses 
top and bottom has an exponent showing.  If it doesn't, give 
it a 1 exponent:

{{{((3^1x^2)/(5^1x^1y^5))^3}}}

Next we remove the parentheses by multiplying every exponent inside
the parentheses by the 3 exponent just outside the parentheses on 
the right:

{{{(3^(1*3)x^(2*3))/(5^(1*3)x^(1*3)y^(5*3))}}}

{{{(3^3x^6)/(5^3x^3y^15)}}}

3³ = 3·3·3 = 27
5³ = 5·5·5 = 125

Replace those:

{{{(27x^6)/(125x^3y^15)}}}

Finally subtract the exponent of
x<sup>3</sup> from the exponent of x<sup>6</sup>
getting x<sup>3</sup>, and place it in the
numerator because the larger exponent x<sup>6</sup>
was in the numerator, removing the x³ from
the denominator.

 {{{(27x^3)/(125y^15)}}}

Edwin</pre>