Question 711244
{{{(8+i)(2+i)}}}
{{{16+2i+8i+i^2}}}
Simplify the i terms:
{{{16+10i+i^2}}}
i^2=-1, so substitute that:
{{{16+10i-1}}}
Simplify and you are done:
{{{highlight(15+10i)}}}
=================
Good Luck,
tutor_paul@yahoo.com