Question 711154
   solution has 6 %  alcohol  and solution B has 20 % alcohol
 mixture has 14 % alcohol
   ration of   solution A & solution  B   to be mixed to get  14% alcohol mixture   =  ( 20 -14 ) : ( 14-6)
 = 6: 8
= 3: 4
 so solution A should be mixed 3 parts  and  solution B should be mixed 4 parts
  solution A = 600 ml
  let the quantity of solution B be x ml
 then 600 : x  = 3:4 
 600/x  = 3/4
 x  = 600 * 4/3   = 800 ml
 so  quantity of solution B  is 800 ml