Question 710732
There's not much to understand.  The formula is like a recipe...plug in the numbers and variables.<P>
{{{a^3-b^3=(a-b)*(a^2+ab+b^2)}}}<P>
Recognize that the initial expression is the difference of two cubes.  {{{8y^3=(2y)^3)}}} so a=2y.  {{{1=1^3}}} so b=1.<P>
The factored form is {{{(2y-1)*((2y)^2+(2y*1)+1^2)=(2y-1)*(4y^2+2y+1)}}}
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