<PRE><B>Question 710614</B>
we started with 17 gallons of antifreeze that was 90% water and 10% antifreeze. We added 2 gallons of pure water and one gallon of pure antifreeze. Determine what percentage of the resulting mix is water and what percent is antifreeze.
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Equation:
water + water = water
0.90*17 + 1*2 = x(17+2)
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90*17 + 100*2 = 19x
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x = 91.05% (percent of water in the mix)
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100-91.05 = 8.95% (percent of antifreeze in the mix)
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Cheers,
Stan H.</PRE>