Question 62903
graph the inequalities:  
1st: y>x^2+x-6    
2nd: y<x+3 
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You have to graph the equalities in dashed-line form:
the 1st inequality is inside the parabola. 
The 2nd inequality is below the line.
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The intersection of the two areas is the solution
set for the system.

{{{graph(300,200,-10,10,-10,10,x^2+x-6,x+3)}}}
Cheers,
Stan H.