Question 710606


 let {{{x}}} be first even integer

{{{x + 2}}} second even integer

{{{x + 4}}} third even integer

if {{{4}}} times the {{{first}}} minus {{{twice}}} the {{{third}}} is {{{equal}}} to the {{{second}}}, we have

{{{4x-2(x + 4)=x + 2}}}..........solve for {{{x}}}

{{{4x-2x-8=x + 2}}}

{{{2x-8=x + 2}}}

{{{2x-x=8 + 2}}}

{{{highlight(x=10)}}}........first even integer

{{{x + 2}}} 

{{{10 + 2}}}

{{{highlight(12)}}}..........second even integer


{{{x + 4}}} 

{{{10 + 4}}}

{{{highlight(14)}}}..........third even integer