Question 710565
solve the equation. 
log base b (X+3) = log base b (8) - log base b (2)
logb(x+3)-logb(8)+logb(2)=0
logb[(x+3)*2/8]=logb(1)
(x+3)*2/8=1
x+3=4
x=1
check:
logb(x+3)=logb(4)
logb(8)-logb(2)=logb(8/2)=logb(4)