Question 708362
Please help me solve this problem: 
log16x+log4x+log2x=7
convert to base 2:
log2(x)/log2(16)+log2(x)/log2(4)+log2(x)=7
log2(x)/4+log2(x)/2+log2(x)=7
LCD:4
log2(x)+2log2(x)+4log2(x)=4*7
log2[x*(x)^2*x^4]=28
log2[x*x^2*x^4]=28
log2[x^7]=28
convert to exponential form
2^28=x^7
x^7=2^28
x=(2^28)(1/7)
x=2^4
x=16
check: Using log key on calculator
log16(x)=log(16)/log(16)=1
log4(x)=log(16)/log(4)=2
log2(x)=log(16)/log(2)=4
log16x+log4x+log2x=1+2+4=7