Question 710492
Find the integer such that twice its squares added to itself makes 15.
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Equation:
2x^2 + x = 15
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2x^2 + x - 15 = 0
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2x^2 + 6x - 5x - 15 = 0
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2x(x+3)-5(x+3) = 0
(x+3)(2x-5) = 0
x = -3 or x = 5/2
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Ans: Integer solution: x = -3
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Cheers,
Stan H.
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