Question 710295
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Solve one of the equations for one of the variables in terms of the other.  For example *[tex \LARGE x\ -\ 2y\ =\ 3] is equivalent to *[tex \LARGE x\ =\ 2y\ +\ 3].


Then substitute the expression in *[tex \LARGE y] for *[tex \LARGE x] in the second equation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4(2y\ +\ 3)\ -\ 8y\ =\ 12]


Solve the resulting single variable equation.  You will either get a single answer which you then substitute back in to either of the original equations, or...


You will get a triviality, such as *[tex \LARGE 0\ =\ 0].  This means that the solution set of the system has infinite elements, or...


You will get an absurdity, such as *[tex \LARGE 3\ =\ 10].  This means that the solution set of the system is the empty set.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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