Question 62854
The half-life of readioactive carbon-14 is 5,700 years. How much of an initial sample will remain after 3,000 years? 
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A(t)=Ao (1/2)^(t/5700)
A(3000)=A(0)(1/2)^(3000/5700)
A(3000)=A(0)[0.694]
69.4% of the original amount will remain.
Cheers,
Stan H.