Question 709881
To solve for x, first factor out an x from the left side of the equal sign.  This gives us


{{{x(x^2 - 6x - 9) = 0}}}


We know know that 0 is one of the values of x.


To find the other two values, use the quadratic formula on the quadratic equation inside the parentheis:  {{{x^2 - 6x - 9}}}


{{{x=(-(-6)+-sqrt(-6^2-4*1*(-9)))/(2*1)}}} = 


{{{x = (6+-sqrt(36+36))/2}}} =


{{{x = (6+-sqrt(72))/2}}} = 

{{{x = (6+-6*sqrt(2))/2}}}


We can reduce this to lowest terms, by factoring out a 6 from the numerator:


{{{x = (6(1+-sqrt(2)))/2}}}, then dividing the factored 6, by two, giving us


{{{x = 3(1+-sqrt(2))}}}


Therefore, x = 0,{{{3+3*sqrt(2))}}},{{{3-3*sqrt(2))}}}