Question 709848
{{{ 2x+4=8y}}}...here you have a linear equation and graph is a line

to graph it, all you need is two points that lie on a line, and easiest way is to find {{{x-intercept}}} and {{{y-intercept}}}

to find {{{x-intercept}}}, set {{{y=0}}} and solve {{{ 2x+4=8y}}} for {{{x}}}

{{{ 2x+4=8*0}}}

{{{ 2x+4=0}}}

{{{ 2x=-4}}}

{{{ x=-4/2}}}

{{{ highlight(x=-2)}}}...so,{{{x-intercept}}} is at ({{{-2}}},{{{0}}})

now find  {{{y-intercept}}}

to find {{{y-intercept}}}, set {{{x=0}}} and solve {{{ 2x+4=8y}}} for {{{y}}}

{{{ 2*0+4=8y}}}

{{{ 0+4=8y}}}

{{{ 8y=4}}}

{{{ y=4/8}}}

{{{ highlight(y=1/2)}}}...so,{{{y-intercept}}} is at ({{{0}}},{{{1/2}}})

plot these two points and draw a line through



{{{drawing(600,600,-5,5,-5,5,grid(0),circle(0,1/2,0.1),circle(-2,0,0.1),graph(600,600,-5,5,-5,5,(1/4)x+1/2))}}}