Question 709838
The sum of the measures of the interior angles of a polygon with {{{n}}} sides is
{{{(n-2)180^o}}}
The sum of the exterior angles of any polygon is {{{360^o}}}.
{{{(n-2)180^o=360^o}}} --> {{{n-2=360^o/180^o}}} --> {{{n-2=2}}} --> {{{highlight(n=2)}}}