Question 709762
Let {{{ x }}} = original amount of dirt
{{{ (3/4)*x }}} is poured out, and
{{{ (1/4)*x }}} remains in the bucket
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{{{ (2/3)*(3/4)*x = (1/2)*x }}} is poured back in
{{{ (1/4 + 1/2)*x = (3/4)*x }}} is now in the bucket
20% is spilled out, so 80% remains
80% = {{{ 4/5 }}}
{{{ (4/5)*(3/4)*x = (3/5)*x }}}
{{{ 3/5}}} = 60%
60% of the original dirt remains in the bucket