Question 709750
{{{ (y-10)+(z+1)+(x-4)  = x + y + z - 10 + 1 - 4 }}}
{{{ (y-10)+(z+1)+(x-4)  = x + y + z - 13 }}}
and, since
{{{ x + y + z = 22 }}},
by substitution,
{{{ (y-10)+(z+1)+(x-4)  = 22 - 13 }}}
{{{ (y-10)+(z+1)+(x-4)  = 9 }}}