Question 709593
Square with side length x.  Area is {{{x^2}}}.


Triangle base 64, height x.  Area is {{{(1/2)*64*x}}}.


We are given that {{{x^2=(1/8)*(1/2)*64*x}}}.
{{{x^2=(1/8)*(1/2)*8*2*4*x}}}
{{{x^2=4x}}}
{{{x(x-4)=0}}}
.
{{{highlight(x=4)}}}