Question 709617
f(x)= 3x/1+x, x≥0
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A) Find the range
The horizontal asymptote is y = 3.
Since the domain is x>=0, range is {0,3)

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b)For which values is f(x)=2
Solve (3x)/(1+x) = 2
3x = 2+2x
x = 2
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Graph, so you can see why range is [0,3)
{{{graph(400,400,-10,10,-10,10,(3x)/(1+x))}}}
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Cheers,
Stan H.